3.2x^2-6.5x+1=0

Solution for 3.2x^2-6.5x+1=0 equation:

3.2x^2-6.5x+1=0

a = 3.2; b = -6.5; c = +1;
Δ = b2-4ac
Δ = -6.52-4·3.2·1
Δ = 29.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.5)-\sqrt{29.45}}{2*3.2}=\frac{6.5-\sqrt{29.45}}{6.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.5)+\sqrt{29.45}}{2*3.2}=\frac{6.5+\sqrt{29.45}}{6.4}
$